In a 1-D elastic collision between two equal masses, one moving at v and the other at rest, what are the velocities after the collision?

Answer: The first stops; the second moves at v A classic result: for equal masses in a 1-D elastic collision, the projectile stops and the target takes on the projectile's velocity.

In a perfectly <strongelastic</strong collision, which of the following is conserved?

Answer: Both momentum and kinetic energy By definition, elastic collisions conserve both momentum and KE. Inelastic collisions only conserve momentum.

A 2000\text{kg} truck at 10\text{m/s} collides with a 1000\text{kg} car at rest. They stick. Common velocity?

Answer: 6.7\text{m/s} v' = (2000 \cdot 10)/3000 \approx 6.67\text{m/s}.

AP Physics 1 · Topic 4.4

Elastic and Inelastic Collisions Practice

Q: In a perfectly <strongelastic</strong collision, which of the following is conserved?

Answer: Both momentum and kinetic energy By definition, elastic collisions conserve both momentum and KE. Inelastic collisions only conserve momentum.

Q: A 2000\text{kg} truck at 10\text{m/s} collides with a 1000\text{kg} car at rest. They stick. Common velocity?

Answer: 6.7\text{m/s} v' = (2000 \cdot 10)/3000 \approx 6.67\text{m/s}.

Part of Linear Momentum.(TOP-4.D)

Practice questions

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Sample questions

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Sample 1difficulty 2/5
$v$
- A
  $v$
  check_circle
- B
  $v/2$
- C
  $-v$
- D
  $Both stop$
Why
$A classic result: for equal masses in a 1-D elastic collision, the projectile stops and the target takes on the projectile's velocity.$
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Sample 2difficulty 2/5
$In a perfectly <strong> elastic </strong> collision, which of the following is conserved?$
- A
  $Momentum only$
- B
  $Both momentum and kinetic energy$
  check_circle
- C
  $Kinetic energy only$
- D
  $Neither$
Why
$By definition, elastic collisions conserve both momentum and KE. Inelastic collisions only conserve momentum.$
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Sample 3difficulty 2/5
$2000~\text{kg}$
- A
  $3.3~\text{m/s}$
- B
  $10~\text{m/s}$
- C
  $6.7~\text{m/s}$
  check_circle
- D
  $5.0~\text{m/s}$
Why
$v' = (2000 \cdot 10)/3000 \approx 6.67~\text{m/s}$
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Sample 4difficulty 2/5
$3.0~\text{kg}$
- A
  $2.0~\text{m/s}$
- B
  $1.0~\text{m/s}$
- C
  $4.0~\text{m/s}$
- D
  $3.0~\text{m/s}$
  check_circle
Why
$(3.0)(4.0) + 0 = (3.0 + 1.0)v' \Rightarrow v' = 12/4 = 3.0~\text{m/s}$
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Sample 5difficulty 2/5
$Two carts approach each other on a frictionless track and stick together at collision. Common velocity afterward?$
- A
  $+1.5~\text{m/s}$
- B
  $+2.0~\text{m/s}$
  check_circle
- C
  $+3.0~\text{m/s}$
- D
  $+5.0~\text{m/s}$
Why
$p_i = (3)(4) + (2)(-1) = 12 - 2 = 10$
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